What was the cannon ball's velocity when it left the cannon?Īnswer: The velocity of the cannon ball can be found by rearranging the horizontal range formula: The trajectory equation is the path taken by a particle during projectile motion.
The pirate watched the cannon ball, and noted that it hit the water 800 m away. Horizontal Range of the projectile is: Horizontal Range(R) u2sin2/g ( sin2 2cossin ) The Equation of Trajectory. This is slightly greater than the 75.0 m width of the gorge, so she will make it to the other side.Ģ) A pirate fired one of the ship's cannons to test its range. The motorcyclist's horizontal range will be 76.8 m, if she takes off from the ramp at 28.0 m/s. When the angle of projection is 45, the maximum range is obtained. What is range in projectile motion R horizontal range (m) V0 initial velocity (m/s) G acceleration due to gravity (9. After testing the predicted range the calculated average of the 10 launches came to. The measured initial velocity and height were used in a kinematic equation that was converted into the predicted range equation to calculate a predicted range of. At that velocity, what will be her horizontal range, and will she make it to the other side of the gorge?Īnswer: The motorcyclist's horizontal range can be found using the formula: Maximum Range: It is the longest distance covered by the object during projectile motion. Projectile Motion equations were used to predict the range in this projectile motion lab. She plans to take off from the ramp at a velocity of 28.0 m/s. The ramp is inclined at 53.1° from the horizontal plane. 1) A motorcyclist has set up a stunt with a ramp at the edge of a gorge 75.0 m wide.